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Section 8.1 Law of Sines

The Law of Sines relates the sides and angles of any triangle (not just right triangles).
In other words, the ratio of a side to the sine of its opposite angle is equal for all three sides of the triangle.
The law of sines can also be rewritten with the side lengths in the denominator,
\begin{equation*} \frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c} \end{equation*}
This is because you can take the reciprocal of all three sides of the equation (in other words, flip them all upside down).
By convention, you should always label the triangle to align with the law of sines, so that each side letter is opposite its angle letter. In other words, side \(a\) is opposite angle \(A\text{,}\) side \(b\) is opposite angle \(B\text{,}\) and side \(c\) is opposite angle \(C\text{.}\)
Figure 8.1.2. Standard triangle labeling for Law of Sines

Subsection 8.1.1 Placeholder Formulas in Trigonometry

When using the law of sines, the letters don’t dictate a specific angle or side. You could swap \(A\) and \(C\) and the formula would still be valid. You just have to swap \(a\) and \(c\) also. The only requirement is that \(a\) must be the side across from angle \(A\text{,}\) \(b\) across from \(B\text{,}\) and \(c\) across from \(C\text{.}\)
This means that the law of sines can be summarized in only one statement,
\begin{equation*} \frac{a}{\sin{A}} = \frac{b}{\sin{B}} \end{equation*}
Basically, in any triangle, the ratio of side over sine of its opposite angle, equals any other side over the sine of its opposite angle.

Remark 8.1.3. Placeholder Formulas.

This means that law of sines is a so-called β€œplaceholder formula”, in that the symbols \(A, B, C\) and \(a, b, c\) do not necessarily refer to specific sides or angles. They are just placeholders or β€œstand-ins” for the 3 sides and angles of a triangle. In contrast, some formulas use variables that have a universally agreed-upon meaning. For example, in the quadratic formula,
\begin{equation*} ax^2 + bx + c = 0 \quad \rightarrow \quad x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \end{equation*}
The letter \(a\) always represents the coefficient of \(x^2\text{,}\) \(b\) is the coefficient of \(x\text{,}\) and \(c\) is the constant. You can’t switch \(a\) and \(b\) without changing the meaning of the formula.

Subsection 8.1.2 Examples

Example 8.1.4. Finding a Side (AAS).

In triangle \(ABC\text{,}\) \(\angle A = 35Β°\text{,}\) \(\angle B = 88Β°\text{,}\) and \(AC = 44\) mm. Determine the length of \(AB\text{.}\)
Figure 8.1.5. Triangle with angles 35Β° and 88Β°
Answer.
\(AB \approx 36.9\) mm

Example 8.1.6. Finding a Side with Obtuse Angle.

In triangle \(ABC\text{,}\) \(\angle A = 52Β°\text{,}\) \(\angle B = 118Β°\text{,}\) and \(BC = 45\) m. Determine the length of \(AB\text{.}\)
Figure 8.1.7. Triangle with obtuse angle 118Β°
Answer.
\(AB \approx 9.9\) m

Example 8.1.8. Finding an Angle.

In triangle \(ABC\text{,}\) \(\angle B = 62Β°\text{,}\) \(AC = 28\) m, and \(BC = 31\) m. Determine the measure of angle \(A\text{.}\)
Figure 8.1.9. Triangle with known angle and two sides
Answer.
\(A \approx 78.9Β°\)

Example 8.1.10. Finding an Angle (Obtuse Given Angle).

In triangle \(ABC\text{,}\) \(\angle B = 98Β°\text{,}\) \(AC = 17.5\) m, and \(BC = 15\) m. Determine the measure of angle \(A\text{.}\)
Figure 8.1.11. Triangle with obtuse angle 98Β°
Answer.
\(A \approx 58.0Β°\)
To solve an oblique triangle means to determine the lengths of all of its sides and the measure of all of its angles.

Example 8.1.12. Solving a Triangle (AAS).

Solve the triangle: \(\angle B = 67Β°\text{,}\) \(AC = 13\) m, and \(BC = 12\) m.
Figure 8.1.13. Triangle to solve
Answer.
\(A \approx 58.5Β°\text{,}\) \(C \approx 54.5Β°\text{,}\) \(AB \approx 11.6\) m

Example 8.1.14. Solving a Triangle (ASA).

Solve the triangle: \(\angle A = 42Β°\text{,}\) \(\angle B = 64Β°\text{,}\) and \(AC = 50\) m.
Figure 8.1.15. Triangle with two known angles
Answer.
\(C = 74Β°\text{,}\) \(AB \approx 53.5\) m, \(BC \approx 37.2\) m

Example 8.1.16. Solving a Triangle with Obtuse Angle.

Solve the triangle: \(\angle A = 22Β°\text{,}\) \(\angle C = 39Β°\text{,}\) and \(AB = 29\) mm.
Figure 8.1.17. Triangle with small angle
Answer.
\(B = 119Β°\text{,}\) \(AC \approx 40.3\) mm, \(BC \approx 17.3\) mm

Example 8.1.18. Solving a Triangle.

Solve the triangle: \(\angle A = 48Β°\text{,}\) \(\angle C = 61Β°\text{,}\) and \(AB = 21\) cm.
Figure 8.1.19. Triangle to solve
Answer.
\(B = 71Β°\text{,}\) \(AC \approx 22.7\) cm, \(BC \approx 17.8\) cm

Subsection 8.1.3 Practice Problems

Exercise Group 8.1.1. Finding Sides with Law of Sines.

Sketch each triangle and determine the measure of the indicated side.
(a)
In \(\triangle ABC\text{,}\) \(\angle A = 57Β°\text{,}\) \(\angle B = 73Β°\text{,}\) and \(AB = 24\) cm. Find the length of \(AC\text{.}\)
Answer.
\(AC \approx 27.4\) cm
(b)
In \(\triangle ABC\text{,}\) \(\angle B = 38Β°\text{,}\) \(\angle C = 56Β°\text{,}\) and \(BC = 63\) cm. Find the length of \(AB\text{.}\)
Answer.
\(AB \approx 75.7\) cm
(c)
In \(\triangle ABC\text{,}\) \(\angle A = 50Β°\text{,}\) \(\angle B = 50Β°\text{,}\) and \(AC = 27\) m. Find the length of \(AB\text{.}\)
Answer.
\(AB = 27\) m
(d)
In \(\triangle ABC\text{,}\) \(\angle A = 23Β°\text{,}\) \(\angle C = 78Β°\text{,}\) and \(AB = 15\) cm. Find the length of \(BC\text{.}\)
Answer.
\(BC \approx 6.0\) cm