Skip to main content\(\newcommand{\N}{\mathbb N}
\newcommand{\Z}{\mathbb Z}
\newcommand{\Q}{\mathbb Q}
\newcommand{\R}{\mathbb R}
\newcommand{\abs}[1]{\left\lvert #1 \right\rvert}
\newcommand{\set}[1]{\left\{ #1 \right\}}
\renewcommand{\neg}{\sim}
\newcommand{\brac}[1]{\left( #1 \right)}
\newcommand{\rad}[1]{#1 \ \text{rad}}
\newcommand{\eval}[1]{\left. #1 \right|}
\newcommand{\floor}[1]{\left\lfloor #1 \right\rfloor}
\newcommand{\ceil}[1]{\left\lceil #1 \right\rceil}
\newcommand{\ang}[1]{#1^\circ}
\newcommand{\crossmethod}[4]{
\begin{tikzpicture}[baseline=(M.base)]
\node (M) at (0,0) {$#1$};
\node (P) at (0,-1) {$#2$};
\node (N) at (1.5,0) {$#3$};
\node (Q) at (1.5,-1) {$#4$};
\draw (M) -- (Q);
\draw (P) -- (N);
\end{tikzpicture}
}
\newcommand{\lt}{<}
\newcommand{\gt}{>}
\newcommand{\amp}{&}
\definecolor{fillinmathshade}{gray}{0.9}
\newcommand{\fillinmath}[1]{\mathchoice{\colorbox{fillinmathshade}{$\displaystyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\textstyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\scriptstyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\scriptscriptstyle\phantom{\,#1\,}$}}}
\)
Section 13.7 Solving Logarithmic Equations
Subsection 13.7.1 Examples
Exercise Group 13.7.1. Basic Equations.
(a)
\(\log_8(6x-3)=\log_8(4x+7)\)
(b)
\(\log{x}+\log{x}=\log{49}\)
Answer.
\(x=7\) (reject
\(x=-7\))
(c)
\(\log_5{(x+1)} - \log_2{(x-3)} = 1\)
(d)
\(\log_{4}(x^2+1)-\log_{4}{6}=\log_{4}{5}\)
(e)
\(3\log_{6}{x}=\log_{6}{125}\)
Exercise Group 13.7.2. Intermediate Equations.
(a)
\(\log_{3}(9x) + \log_{3}x = 4\)
Answer.
\(x = 3\) (reject
\(x = -3\))
(b)
\(\log_{3} x + \log_{3}(x-4) = \log_3 12\)
Answer.
\(x = 6\) (reject
\(x = -2\))
(c)
\(\log_5{(x-1)}+\log_5{3}=\log_5{x}\)
(d)
\(\log_{6}(x+3)+\log_{6}(x+4)=1\)
Answer.
\(x=-1\) (reject
\(x=-6\))
(e)
\(2 \log_3{x}-\log_3(x+2) = 0\)
Answer.
\(x=2\) (reject
\(x=-1\))
(f)
\(\log_2(x-3)+\log_2{x}=2\)
Answer.
\(x=4\) (reject
\(x=-1\))
(g)
(h)
\(\log_3{(x+6)}-\log_3{(x+2)}=\log_3{x}\)
Answer.
\(x = 2\) (reject
\(x = -3\))
(i)
\(2\log_{2}{x}-\log_{2}{x}=3\)
(j)
\(\log(2x+4)-\log(x+2)=\log(x+1)\)
Answer.
\(x=1\) (reject
\(x=-2\))
(k)
\(2\log_{2}(x-4)-\log_2{x}=1\)
(l)
\(\log(6x)=\log(x+6)+\log(x-1)\)
Answer.
\(x=3\) (reject
\(x=-2\))
(m)
\(\log_4(x+7)=2-\log_4(x+1)\)
Answer.
\(x=1\) (reject
\(x = -9\))
(n)
\(\log_2{(2x+4)}-\log_2{(x-1)}=\log_3{27}\)
(o)
\(\log{(x+2)}+\log{(x-1)}=1\)
Answer.
\(x=3\) (reject
\(x=-4\))
(p)
\(\log_{15}{(x+2)}+\log_{15}{x}=1\)
Answer.
\(x=3\) (reject
\(x=-5\))
(q)
\(\log_{3}{(x+3)}=1-\log_{3}{(x+5)}\)
Answer.
\(x=-2\) (reject
\(x=-6\))
(r)
\(\log{(x-3)}+\log{(x+4)}-\log{x}=\log{5}\)
Answer.
\(x=6\) (reject
\(x=-2\))
(s)
Answer.
\(x=2\) (reject
\(x=-5\))
(t)
\(\log_3(x+6)-\log_3(x+2)=\log_3{x}\)
Answer.
\(x=2\) (reject
\(x=-3\))
Exercise Group 13.7.3. Mixed Equations.
(a)
(b)
\(\log_5(2x-1)+\log_5(x-2)=1\)
Answer.
\(x=3\) (reject
\(x=-\frac{1}{2}\))
(c)
\(\log{(2x+1)}-\log{(-x+1)}=1\)
(d)
\(\log_5{(x-18)}-\log_5{x}=\log_5{7}\)
Answer.
no solution (reject
\(x=-3\))
(e)
\(2\log_3{(3-x)} = \log_3{4} + \log_3{(6-x)}\)
Answer.
\(x = -3\) (reject
\(x = 5\))
(f)
\(\log(2x-3)+\log(x-2)=\log(2x-1)\)
Answer.
\(x=\frac{7}{2}\) (reject
\(x=1\))
(g)
\(\log(x-4)+\log(x+1)=\log(x-8)\)
Answer.
no solution (reject
\(x=2\))
(h)
\(\log_2(2-2x)+\log_2(1-x)=5\)
Answer.
\(x=-3\) (reject
\(x=5\))
(i)
\(\log_{5}(3x+1)+\log_{5}(x-3)=3\)
Answer.
\(x=8\) (reject
\(x=-\frac{16}{3}\))
(j)
\(\log_2(3x+1)+\log_2(x-1)=\log_2(10x+14)\)
Answer.
\(x=5\) (reject
\(x=-1\))
(k)
\(2\log(4-x)-\log{3}=\log(10-x)\)
Answer.
\(x=-2\) (reject
\(x=7\))
(l)
\(\log_2{(x-3)}+\log_2{(x-2)}=2+\log_2{5}\)
Answer.
\(x=7\) (reject
\(x=-2\))
(m)
\(\log_2{(\log_{3}{27})}=x\)
(n)
\(\log_{2}{(x^2-12)}-\log_{2}{1}=\log_{2}{x}\)
Answer.
\(x=4\) (reject
\(x=-3\))
(o)
\(2\log_2(x+2)-\log_2(3x-2)=2\)
(p)
\(2\log_4{x}+\log_4{(x-2)}-\log_4{(2x)}=1\)
Answer.
\(x=4\) (reject
\(x=-2\))
(q)
\(2\log_3{x}+\log_3{(x-1)}=1+\log_3{(2x)}\)
Answer.
\(x=3\) (reject
\(x=-2\))
Exercise Group 13.7.4. Advanced Examples.
(a)
\(\log_2{(x+1)} + \log_2{x} = \log_2{5}\)
Hint.
quadratic equation, solve using the quadratic formula
Answer.
\(x = \frac{-1+\sqrt{21}}{2} \approx 1.79\) (reject
\(x = \frac{-1-\sqrt{21}}{2} \approx -2.79\))
(b)
\(\log_4(3x^2-5x-2)-\log_4(x-2)=1\)
Answer.
no solution (reject
\(x=1,2\))
(c)
\(\log_{25}(x-1)+\log_{25}(x+3)=\log_7\sqrt{7}\)
Answer.
\(x=2\) (reject
\(x=-4\))
(d)
\(\frac{1}{2}-\log_{16}(x-3)=\log_{16}x\)
Answer.
\(x=4\) (reject
\(x=-1\))
(e)
\(\log_{36}(x-2)+\log_{36}(x+1)+\log_{36}(x-3)=\frac{1}{2}\)
Hint.
Factor the common factor, and then use the quadratic formula
Answer.
\(x=2+\sqrt{3}\) (reject
\(x=0,2-\sqrt{3}\))
(f)
\(\log_{1/4}(x^2+2)-\log_{1/4}(x^2-x)=-2\)
Hint.
\(15x^2-16x-2=0\text{,}\) use the quadratic formula
Answer.
\(x = \frac{8 \pm \sqrt{94}}{15} \approx 1.18, -0.11\)